Page 114 - Physics Form 5 KSSM_Neat
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Example         1

                                                                                  LET’S ANSWER
            Three resistors are arranged in series and in parallel as shown in Figure 3.13.   LET’S ANSWER
            The resistance for R , R  and R  are 2 W, 4 W and 12 W respectively.
                              1  2     3
                          6 V
            KEMENTERIAN PENDIDIKAN MALAYSIA
                                                    R 2
                             A               A                                      https://bit.
                              1     R         2
                                     1                                              ly/32J6R7B
                                                    R 3
                                             A
                                              3
                                     Figure 3.13
            When the switch is closed, calculate:
            (a)  the effective resistance, R
            (b) the current flowing through the 2 W resistor and the potential difference across it
            (c)  the current flowing through the 4 W and 12 W resistors and the potential difference across
                them respectively
              Solution

            (a)                        R
                   6 V                  4                  6 V
                                       R 2
                      A    R     A 2                          A
                       1    1                                  1    R 1      R 4
                                       R 3
                                 A                                  2 Ω
                                  3
                Total resistance in the parallel circuit, Thus, the effective resistance in the complete circuit,
                 1  =   +   1                       R = R  + R 4
                      1
                                                         1
                R    R    R                           = 2 + 3
                  4   2    3                          = 5 W
                   =  1   +   1
                      4   12
                      4
                   =
                     12
                     12
                R   =
                  4   4
                   = 3 W
            (b) Total current flowing in the circuit,
                I  =  V                                  6 V
                    R                                         I                    R
                I  =   6                                                       A     2
                    5                                                           2
                  = 1.2 A                                   A 1  I    R     I 2     V 2
                                                                 1     1
                I  = I
                 1                                                   V      I
                Thus, the potential difference for V  = I R            1     3  A   R 3
                                                    1
                                               1
                                                  1
                V  = 1.2 (2)                                                    3
                 1
                  = 2.4 V                                                           V 3
                                                                          V
            104                                                                         LS     3.2.2
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