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                       it has a direct relationship with a third scale to be described
                       shortly, the Kelvin scale. Both scales have arbitrarily assigned   EXAMPLE 4.2
                       reference points and an arbitrary number line that indicates   A bank temperature display indicates 20°C (room temperature). What
                       relative temperature changes. Zero is simply one of the points   is the equivalent temperature on the Fahrenheit scale?  (Answer: 68°F)
                       on each number line and does not mean that there is no tem-
                       perature. Likewise, since the numbers are relative measures
                       of temperature change, 2° is not twice as hot as a temperature
                       of 1° and 10° is not twice as hot as a temperature of 5°. Th e   There is a temperature scale that does not have arbitrarily

                        numbers simply mean some measure of temperature  rela-  assigned reference points, and zero does mean nothing. Th is is
                        tive to the freezing and boiling points of water under normal   not a relative scale but an absolute temperature scale called the
                         conditions.                                           Kelvin scale. The Kelvin scale was proposed in 1848 by William

                           You can convert from one temperature to the other by   Thompson (1824–1907), who became Lord Kelvin in 1892. Th e

                        considering two differences in the scales: (1) the diff erence   zero point on the Kelvin scale is thought to be the lowest limit

                       in the degree size between the freezing and boiling points on   of temperature. Absolute zero is the lowest temperature possible,
                       the two scales and (2) the difference in the values of the lower   occurring when all random motion of molecules was histori-

                        reference points.                                      cally projected to cease. Absolute zero is written as 0 K. A degree

                           The Fahrenheit scale has 180° between the boiling and   symbol is not used, and the K stands for the SI standard scale
                       freezing points (212°F – 32°F), and the Celsius scale has 100°   unit, Kelvin. The Kelvin scale uses the same degree size as the

                       between the same two points. Therefore, each Celsius degree   Celsius scale, and –273°C = 0 K. Note in Figure 4.7 that 273 K

                       is 180/100, or 9/5, as large as a Fahrenheit degree. Each Fahr-  is the freezing point of water, and 373 K is the boiling point. You
                       enheit degree is 100/180, or 5/9, of a Celsius degree. You know   could think of the Kelvin scale as a Celsius scale with the zero
                       that this is correct because there are more Fahrenheit degrees   point shifted by 273°. Thus, the relationship between the Kelvin


                       than Celsius degrees between freezing and boiling. Th e rela-  and Celsius scales is
                       tionship between the degree sizes is 1°C = 9/5°F and 1°F =
                       5/9°C. In addition, considering the difference in the values of            T K  = T C  + 273

                       the lower reference points (0°C and 32°F) gives the equations                                   equation 4.3
                       for temperature conversion. (For a review of the sequence
                       of mathematical operations used with equations, refer to the   A temperature of absolute zero has never been reached, but
                       “Working with Equations” section in the Mathematical Review   scientists have cooled a sample of sodium to 700 nanokelvins,
                       of appendix A.)                                         or 700 billionths of a kelvin above absolute zero.
                                               9 _
                                          T F  =      T C  + 32°


                                               5
                                                                               EXAMPLE 4.3
                                                                equation  4.1
                                                                               A science article refers to a temperature of 300.0 K. (a) What is
                                              5 _                              the equivalent Celsius temperature? (b) Th e  equivalent  Fahrenheit


                                           C  9
                                           T      =      ( T    F   – 32°)      temperature?
                                                                equation  4.2
                                                                               SOLUTION
                                                                               (a)  The relationship between the Kelvin scale and Celsius scale is
                       EXAMPLE 4.1                                                found in equation 4.3, T K  = T C  + 273. Solving this equation for

                       The average human body temperature is 98.6°F. What is the  equivalent   Celsius yields T C  = T K  – 273.
                        temperature on the Celsius scale?
                                                                                                 T C  = T K  – 273
                                                                                                   = 300.0 – 273
                       SOLUTION                                                                    =  27°C
                                                                                                     9 _
                                             5 _                                                 T F  =     T     + 32°


                                           T      =      ( T    F   – 32°)     (b)                     5       C
                                          C
                                             9
                                             5 _                                                     9 _


                                           =        (98.6° – 32°)                                  =         27.0° + 32°
                                             9                                                       5
                                                                                                     243°
                                                                                                     _
                                             5 _                                                   =     + 32°

                                           =        (66.6°)

                                             9                                                        5
                                             333°
                                             _                                                     = 48.6° + 32°
                                           =
                                              9                                                    =  81°F
                                           = 37°C
                       4-7                                                                     CHAPTER 4  Heat and Temperature   91
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