Page 18 - Spotlight A+ Form 4 & 5 Chemistry KSSM
P. 18

Form
           4
                      Chemistry   Chapter 5 Chemical Bond

                                      5.7

               1.  Sodium chloride, NaCl and hydrogen chloride, HCl are two compounds that consist of chlorine, Cl element.
                  The melting point of sodium chloride, NaCl is 808 °C but the melting point of hydrogen chloride, HCl is
                  –114 °C.  Explain why the melting points of the two compounds are different.   C3
               2.  Table 1 shows the proton number of elements P and Q.
                                            Element          Proton number
                                               P                  12
                    ©PAN ASIA PUBLICATIONS
                                               Q                  17

                                                      Table 1
                  (a)  What type of chemical bond is formed between:  C2
                     (i)  P and Q?
                     (ii)  Q and Q?
                  (b) Explain why the compound formed by P and Q cannot conduct electricity in solid state but can
                     conduct electricity in aqueous or molten state.   C3
                  (c)  State whether the compound formed by Q and Q is an electrical conductor. Explain why.   C3
                  (d) Between  the  compounds  formed  in  (a)(i)  and  (a)(ii),  determine  which  compound  can  dissolve  in:
                        C3
                     (i)   Water
                     (ii)  Ethanol

                    SPM   Simulation HOTS Questions



              1  Which of the following particles contain 10     Examiner’s comment:
                 electrons?   C4                                 •  The properties above are for ionic
        CHAP.    [Proton number: Na = 11, Al = 13]                 compound.                                                                                                                                             CHAP.
        5        I   Al            III  Na +                     •  Lead(II) iodide and sodium chloride                                                                                                                   5
                 II  Na            IV  Al 3+                       are ionic compounds but lead(II) iodide
                 A  I and II       C  II and IV                    is insoluble in water.
                 B  I and III      D  III and IV                 Answer: D

                 Examiner’s comment:                          3.  The electron arrangement of atom J is 2.8.2
                 •  Al contains 13 electrons.                   and the electron arrangement of atom L is 2.7.
                 •  Na contains 11 electrons.
                      +
                 •  Na  is the ion of Na which loses 1 electron.  Elements J and L react to form a compound.
                   Thus, the number of electrons is 10.          Write the chemical formula for the compound
                 •  Al   is the ion of Al which loses 3 electrons.  formed and state two physical properties.
                      3+
                   Thus, the number of electrons is 10.             C4
                 Answer: D
                                                                 Examiner’s comment:
              2  Compound  Z has the following properties.       J is a metal and L is a non-metal. An atom
                 •  Soluble in water                             J will donate 2 electrons. Each of two atom
                 •  Conduct electricity in aqueous or molten     L will receive 1 electron from atom J. The
                   state                                         ionic compound formed has the chemical
                 •  Melting point = 800 °C                       formula JL  .
                                                                          2
                                                                 Answer:
                 What is Z?   C3                                 Chemical formula = JL 2
                 A  Glucose                                      The compound formed is soluble in water
                 B  Naphthalene                                  and has high melting point and boiling
                 C  Lead(II) iodide                              point.
                 D  Sodium chloride



              136
   13   14   15   16   17   18   19   20   21   22   23